[Solved] Bash; HowTo suppress jobstart messages

[dlacx]

Hello bash experts,

The following

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$ echo "Begin"; { sleep 10; echo "1"; } & { sleep 5; echo "2"; } & wait; echo "3";
Begin
[1] 11898
[2] 11899
2
1
[1]-  Done                    { sleep 10; echo "1"; }
[2]+  Done                    { sleep 5; echo "2"; }
3

produces messages as expected. With

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$ echo "Begin"; { sleep 10; echo "1"; } & { sleep 5; echo "2"; } & wait 2>/dev/null; echo "3";
Begin
[1] 11908
[2] 11909
2
1
3

suppress terminating messages, but I could not figure out how to suppress job start messages. The

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$ echo "Begin"; { sleep 10; echo "1" & } 2>/dev/null; { sleep 5; echo "2" & } 2>/dev/null; wait 2>/dev/null; echo "3";
Begin
1
2
3

runs 15secs (somehow "serial" execution manner?).
Many thanks for any help.
Leslie

[fabien]

Hello,

an expert would probably have many interesting things to say. I can only say that

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$> echo "Begin"; { { sleep 10; echo -n "1  "; date; } & { sleep 5; echo -n "2  "; date; } & wait; } 2>/dev/null; echo "3"
Begin
2  Thu Feb  1 13:51:31 CET 2024
1  Thu Feb  1 13:51:36 CET 2024
3
$>

works as you expect.

[dlacx]

@fabien: Perfect! Thank you.

[fabien]

Perfect! Thank you.

My pleasure. I forgot to say, it may be useful to be able to see some stderr messages:

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$> echo "Begin"; { { sleep 3; echo "1"; } & { sleep 1; echo "2"; ls /tchick; ls /tchack 2>&3; } & wait; } 3>&2 2>/dev/null; echo "3"
Begin
2
ls: cannot access '/tchack': No such file or directory
1
3
$>